If the tension in sonometer wire is increased by 21%, compare the initial frequency with the later.
Q.2 (vii) If the tension in sonometer wire is increased by 21%, compare the initial frequency with the later.
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Answer: \(n_1 : n_2 = 10 : 11\)
For a sonometer wire \(n = \dfrac{1}{2l}\sqrt{\dfrac{T}{m}}\), so \(n \propto \sqrt{T}\). New tension \(T_2 = 1.21\,T_1\):
\[\frac{n_1}{n_2} = \sqrt{\frac{T_1}{1.21\,T_1}} = \frac{1}{1.1} = \frac{10}{11}\]
Doubtly AI
· 27 Oct 2026
AI-verified · Oct 2026
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