Two numbers are 30% and 40% less than a third number. By what percent is the first number more than the second?
A. 10%
B. 12.5%
C. \(14\frac{2}{7}\)%
D. \(16\frac{2}{3}\)%
A. 10%
B. 12.5%
C. \(14\frac{2}{7}\)%
D. \(16\frac{2}{3}\)%
Best answer
Answer: D. \(16\frac{2}{3}\)%
Answer: (D) \(16\frac{2}{3}\)%
Shortcut: third = 100, first = 70, second = 60. First is more by 10 on a base of 60 = \(16\tfrac{2}{3}\%\).
Trap: 10 on a base of 70 gives 14 2/7%; the base must be the number being compared with (the second).
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