An ore contains 25% of an alloy, and the alloy contains 90% iron. The rest of the ore has no iron. How many kg of ore are needed to get 45 kg of pure iron?
A. 250 kg
B. 225 kg
C. 200 kg
D. 180 kg
A. 250 kg
B. 225 kg
C. 200 kg
D. 180 kg
Best answer
Answer: C. 200 kg
Answer: (C) 200 kg
Iron in the ore = 90% of 25% = 22.5%.
Ore needed = 45 ÷ 0.225 = 200 kg.
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