A is twice as efficient as B. B starts a work alone and works for 5 days; then A joins him and together they finish the work in 5 more days. How many days would A alone take for the whole work?
A. 12 days
B. 20 days
C. 15 days
D. 10 days
1 answer
Best answer
Answer: D. 10 days
Answer: (D) 10 days
Let B do 1 unit/day; then A does 2 units/day.
Work = B's 5 days + (A+B) for 5 days = 5 × 1 + 5 × 3 = 20 units.
A alone = 20 ÷ 2 = 10 days.
Doubtly AI
· 27 Oct 2026
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