A can do a work in 25 days and B in 20 days. They start together, but A leaves 5 days before the work is finished. In how many days is the work finished?
A. 15 days
B. \(13\frac{1}{3}\) days
C. \(11\frac{1}{3}\) days
D. 12 days
A. 15 days
B. \(13\frac{1}{3}\) days
C. \(11\frac{1}{3}\) days
D. 12 days
Best answer
Answer: B. \(13\frac{1}{3}\) days
Answer: (B) \(13\frac{1}{3}\) days
Let the total time be T days. A works (T − 5) days and B works T days.
\(\frac{T - 5}{25} + \frac{T}{20} = 1\) → 4(T − 5) + 5T = 100 → 9T = 120.
T = \(\frac{40}{3} = 13\tfrac{1}{3}\) days.
Shortcut: in the last 5 days only B works and does 5/20 = 1/4. The other 3/4 is done together at 9/100 per day, taking 25/3 days. Total = 25/3 + 5 = 40/3 days.
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