Explain criss-cross inheritance with reference to bleeder’s disease by suitable charts.
Q.16 Explain criss-cross inheritance with reference to bleeder’s disease by suitable charts.
Q.16 Explain criss-cross inheritance with reference to bleeder’s disease by suitable charts.
Best answer
Answer: Haemophilia (bleeder’s disease) is caused by a recessive X-linked gene (Xh); blood fails to clot because of lack of a clotting factor. Since males have only one X, a single recessive allele makes them haemophilic. The X-linked gene passes from father to daughter and from mother to son — this is criss-cross inheritance.
Chart 1: Haemophilic man × normal woman
| Gametes | Xh | Y |
|---|---|---|
| X | XXh carrier daughter | XY normal son |
| X | XXh carrier daughter | XY normal son |
The father’s gene goes to all daughters (carriers); sons are normal.
Chart 2: Carrier daughter (XXh) × normal man (XY)
| Gametes | X | Y |
|---|---|---|
| X | XX normal daughter | XY normal son |
| Xh | XXh carrier daughter | XhY haemophilic son |
Result: 50% daughters carriers, 50% sons haemophilic. Thus the trait passes from the grandfather through his carrier daughter to the grandson (criss-cross inheritance).
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