Write the degree of the differential equation \((y''')^2 + 3(y'')^3 + 3xy' + 5y = 0\)
Q.2 (iv) Write the degree of the differential equation \((y''')^2 + 3(y'')^3 + 3xy' + 5y = 0\)
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Answer: Degree = 2
The highest order derivative is \(y'''\) (order 3) and its highest power is 2. The equation is polynomial in the derivatives, so the degree is 2.
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· 28 Oct 2026
AI-verified · Oct 2026
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