Find the general solution of \(4\cos^2\theta = 3\).
Q.5 Find the general solution of \(4\cos^2\theta = 3\).
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Answer: \(\theta = n\pi \pm \dfrac{\pi}{6},\ n \in Z\)
\(\cos^2\theta = \dfrac{3}{4} = \left(\dfrac{\sqrt{3}}{2}\right)^2 = \cos^2\dfrac{\pi}{6}\).
The general solution of \(\cos^2\theta = \cos^2\alpha\) is \(\theta = n\pi \pm \alpha\). Hence \(\theta = n\pi \pm \dfrac{\pi}{6}\), where \(n \in Z\).
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· 28 Oct 2026
AI-verified · Oct 2026
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