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Answer: \(\bar{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda(\hat{i} + \hat{j} + \hat{k})\)

\(\bar{a} = \hat{i} + 2\hat{j} + 3\hat{k}\), \(\bar{b} = 2\hat{i} + 3\hat{j} + 4\hat{k}\). The line through \(A\) and \(B\) is \(\bar{r} = \bar{a} + \lambda(\bar{b} - \bar{a})\), and \(\bar{b} - \bar{a} = \hat{i} + \hat{j} + \hat{k}\).

So \(\bar{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda(\hat{i} + \hat{j} + \hat{k})\), \(\lambda\) a scalar.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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