Calculate the maximum velocity of a particle having amplitude of oscillation 4 cm and period 4 seconds.
Q.2 (viii) Calculate the maximum velocity of a particle having amplitude of oscillation 4 cm and period 4 seconds.
1 answer
Best answer
Answer: \(v_{max}\approx 0.0628\) m/s (6.28 cm/s)
\(\omega=\dfrac{2\pi}{T}=\dfrac{2\pi}{4}=\dfrac{\pi}{2}\) rad/s. \(v_{max}=A\omega=0.04\times\dfrac{3.142}{2}=0.06284\) m/s \(\approx 6.28\) cm/s.
Doubtly AI
· 28 Oct 2026
AI-verified · Oct 2026
Report
Was this answer helpful?
Thanks for the feedback.
Sign up free to save answers and ask your own doubts
Your answer
Log in or create a free account to answer this question.