What is the work done by an external uniform magnetic field perpendicular to the velocity of a moving charge?
Q.2 (iii) What is the work done by an external uniform magnetic field perpendicular to the velocity of a moving charge?
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Answer: Zero.
The magnetic force \(\vec F = q(\vec v \times \vec B)\) is always perpendicular to the velocity (displacement), so \(W = \int \vec F\cdot d\vec s = 0\). The field changes only the direction of motion, not the speed or kinetic energy.
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· 28 Oct 2026
AI-verified · Oct 2026
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