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Answer: (i) Open pipe: \(e = \dfrac{n_2l_2 - n_1l_1}{2(n_1 - n_2)}\); (ii) closed pipe: \(e = \dfrac{n_2l_2 - n_1l_1}{n_1 - n_2}\).

The antinode at an open end is formed slightly outside the pipe, at a distance \(e\) called the end correction (\(e \approx 0.3d\), \(d\) = inner diameter). It is found experimentally using two tuning forks of known frequencies \(n_1\) and \(n_2\) (\(n_1 \gt n_2\)). Let \(v\) be the speed of sound in air.

(i) Pipe open at both ends (an end correction at each end, effective length \(l + 2e\)). The pipe length is adjusted so that it resonates in its fundamental mode with fork \(n_1\) at length \(l_1\) and with fork \(n_2\) at length \(l_2\). For the fundamental mode \(\lambda = 2(l + 2e)\), so

\[v = 2n_1(l_1 + 2e) = 2n_2(l_2 + 2e)\]\[n_1l_1 + 2n_1e = n_2l_2 + 2n_2e \Rightarrow 2e(n_1 - n_2) = n_2l_2 - n_1l_1\]\[e = \frac{n_2l_2 - n_1l_1}{2(n_1 - n_2)}\]

(ii) Pipe closed at one end (one end correction, effective length \(l + e\)). The resonating air column lengths for the fundamental mode with forks \(n_1\) and \(n_2\) are \(l_1\) and \(l_2\). For the fundamental mode \(\lambda = 4(l + e)\), so

\[v = 4n_1(l_1 + e) = 4n_2(l_2 + e)\]\[n_1l_1 + n_1e = n_2l_2 + n_2e \Rightarrow e(n_1 - n_2) = n_2l_2 - n_1l_1\]\[e = \frac{n_2l_2 - n_1l_1}{n_1 - n_2}\]

(With a single fork in a resonance tube, the first and second resonance lengths \(l_1\), \(l_2\) give \(l_1 + e = \lambda/4\) and \(l_2 + e = 3\lambda/4\), so \(e = \dfrac{l_2 - 3l_1}{2}\).)

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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