Skip to content
doubtly

1 answer

Best answer

Answer: B. 60

Answer: (b) 60

\(|\bar a \times \bar b|^2 + (\bar a \cdot \bar b)^2 = |\bar a|^2|\bar b|^2\) (since \(\sin^2\theta + \cos^2\theta = 1\)).

\(625 + (\bar a\cdot\bar b)^2 = 25 \times 169 = 4225 \Rightarrow (\bar a\cdot\bar b)^2 = 3600 \Rightarrow |\bar a\cdot\bar b| = 60\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.