Find the co-ordinates of the points of intersection of the lines represented by \(x^2 - y^2 - 2x + 1 = 0\).
Q.6 Find the co-ordinates of the points of intersection of the lines represented by \(x^2 - y^2 - 2x + 1 = 0\).
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Answer: \((1, 0)\)
\(x^2 - 2x + 1 - y^2 = 0 \Rightarrow (x - 1)^2 - y^2 = 0 \Rightarrow (x - 1 - y)(x - 1 + y) = 0\).
So the lines are \(x - y - 1 = 0\) and \(x + y - 1 = 0\). Adding: \(2x - 2 = 0 \Rightarrow x = 1\), and then \(y = 0\).
The lines intersect at \((1, 0)\).
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· 28 Oct 2026
AI-verified · Oct 2026
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