Evaluate : \(\int \frac{1}{\sqrt{x}}\,dx\).
Q.2 (iv) Evaluate : \(\int \frac{1}{\sqrt{x}}\,dx\).
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Answer: \(2\sqrt{x} + c\)
\(\int x^{-1/2}\,dx = \frac{x^{1/2}}{1/2} + c = 2\sqrt{x} + c\).
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· 28 Oct 2026
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