Q.13 Evaluate : ∫₀⁻¹ e^(-x) dx

Answer: 1 - e ∫₀⁻¹ e^(-x) dx = [-e^(-x)]₀⁻¹ = -e¹ - (-e⁰) = -e + 1 = 1 - e .

Evaluate : \(\int_0^{-1} e^{-x}\,dx\)

Q.13 Evaluate : \(\int_0^{-1} e^{-x}\,dx\)

Doubtly Asked 28 Oct 2026 Board exam · July 2025 hsc 12th Save WhatsApp Report

Best answer

Answer: \(1 - e\)

\(\int_0^{-1} e^{-x}\,dx = \left[-e^{-x}\right]_0^{-1} = -e^{1} - (-e^{0}) = -e + 1 = 1 - e\).

Doubtly AI · 28 Oct 2026 AI-generated · not yet verified Report

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