Q.1 (v) The gyromagnetic ratio of electron is _______. A. 2m_e/e B. 2m_e/e² C. e/2m_e D. e²/2m_e

Answer: C. e/2m_e Answer: (c) e/2m_e For an electron in a circular orbit, the orbital magnetic moment is M₀ = evr/2 and the orbital angular momentum is L₀ = m_e vr . The gyromagnetic ratio is M₀/L₀ = e/2m_e , a constant (about 8.8×10¹⁰ C/kg).

The gyromagnetic ratio of electron is _______.

Q.1 (v) The gyromagnetic ratio of electron is _______.

A. \(\dfrac{2m_e}{e}\)

B. \(\dfrac{2m_e}{e^2}\)

C. \(\dfrac{e}{2m_e}\)

D. \(\dfrac{e^2}{2m_e}\)

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Answer: C. \(\dfrac{e}{2m_e}\)

Answer: (c) \(\dfrac{e}{2m_e}\)

For an electron in a circular orbit, the orbital magnetic moment is \(M_0 = \dfrac{evr}{2}\) and the orbital angular momentum is \(L_0 = m_e vr\). The gyromagnetic ratio is \(\dfrac{M_0}{L_0} = \dfrac{e}{2m_e}\), a constant (about \(8.8\times10^{10}\) C/kg).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

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The gyromagnetic ratio of electron is _______.

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