Q.2 (viii) In a hydraulic lift, area of pistons are A₁ and A₂ respectively (A₂ gtgt A₁) . If force F₁ is applied on piston 1, then what is the force exerted on piston 2?

Answer: F₂ = F₁A₂/A₁ . By Pascal’s law the pressure is transmitted equally: F₁/A₁ = F₂/A₂ . Since A₂ gtgt A₁ , the force on piston 2 is much larger than F₁ .

In a hydraulic lift, area of pistons are \(A_1\) and \(A_2\) respectively \((A_2 \gt\gt A_1)\). If force \(F_1\) is applied on piston 1, then what is the force exerted on piston 2?

Q.2 (viii) In a hydraulic lift, area of pistons are \(A_1\) and \(A_2\) respectively \((A_2 \gt\gt A_1)\). If force \(F_1\) is applied on piston 1, then what is the force exerted on piston 2?

Doubtly Asked 28 Oct 2026 Board exam · July 2025 hsc 12th Save WhatsApp Report

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Answer: \(F_2 = F_1\dfrac{A_2}{A_1}\).

By Pascal’s law the pressure is transmitted equally: \(\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}\). Since \(A_2 \gt\gt A_1\), the force on piston 2 is much larger than \(F_1\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

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In a hydraulic lift, area of pistons are \(A_1\) and \(A_2\) respectively \((A_2 \gt\gt A_1)\). If force \(F_1\) is applied on piston 1, then what is the force exerted on piston 2?

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