In a purely resistive circuit a source of e.m.f. having \(e = 140\sin(3142t)\) is connected across a pure resistor. If value of rms current is 1.98 A, calculate the value of resistance.

Q.10 In a purely resistive circuit a source of e.m.f. having \(e = 140\sin(3142t)\) is connected across a pure resistor. If value of rms current is 1.98 A, calculate the value of resistance.

Doubtly Asked 28 Oct 2026 Board exam · July 2025 hsc 12th Save WhatsApp Report

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Answer: \(R \approx 50\ \Omega\)

Peak e.m.f. \(e_0 = 140\) V, so \(e_{rms} = \dfrac{e_0}{\sqrt2} = \dfrac{140}{1.414} = 98.99\) V.

\[R = \frac{e_{rms}}{I_{rms}} = \frac{98.99}{1.98} = 50\ \Omega\]

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

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In a purely resistive circuit a source of e.m.f. having \(e = 140\sin(3142t)\) is connected across a pure resistor. If value of rms current is 1.98 A, calculate the value of resistance.

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