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[Figure: a uniform wire AB, 1 m long, stretched on a metre scale between thick copper strips. The unknown resistance X is connected in the left gap (between A and C) and a resistance box R in the right gap (between C and B). The central point C of the strip is joined through a galvanometer G to a jockey J that slides along the wire. A cell, plug key K and rheostat are connected between A and B.]

Working: The metre bridge works on the principle of the Wheatstone bridge. A suitable resistance R is taken from the box and the key is closed. The jockey is slid along the wire to find the point D where the galvanometer shows no deflection (null point). Let AD = \(l_X\) and DB = \(l_R = 100 - l_X\) cm.

At balance, the four resistances X, R, \(R_{AD}\) and \(R_{DB}\) form a balanced Wheatstone bridge:

\[\frac{X}{R} = \frac{R_{AD}}{R_{DB}} = \frac{\lambda l_X}{\lambda l_R} = \frac{l_X}{l_R}\]

where \(\lambda\) is the resistance per unit length of the uniform wire. Therefore

\[X = R\,\frac{l_X}{100 - l_X}\]

The experiment is repeated for different values of R and with X and R interchanged, and the mean value of X is taken. The null point should be near the middle of the wire for best accuracy.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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