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Answer: B. \(\frac{x^4}{4}+\frac{3x^2}{2}+3\log x-\frac{1}{2x^2}+c\)

Answer: (b) \(\frac{x^4}{4}+\frac{3x^2}{2}+3\log x-\frac{1}{2x^2}+c\)

\(\left(x+\frac{1}{x}\right)^3=x^3+3x+\frac{3}{x}+x^{-3}\).

\(\int\left(x^3+3x+\frac{3}{x}+x^{-3}\right)dx=\frac{x^4}{4}+\frac{3x^2}{2}+3\log x+\frac{x^{-2}}{-2}+c=\frac{x^4}{4}+\frac{3x^2}{2}+3\log x-\frac{1}{2x^2}+c\)

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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