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Answer: \(\frac{100\sqrt{5}}{3}\) sq. units

The parabola is symmetric about the X-axis; for the upper half \(y=5\sqrt{x}\).

Area \(=2\int_0^5 5\sqrt{x}\,dx=10\left[\frac{x^{3/2}}{3/2}\right]_0^5=\frac{20}{3}\left(5^{3/2}\right)=\frac{20}{3}\times5\sqrt{5}=\frac{100\sqrt{5}}{3}\) sq. units.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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