Q.4 (A) (iv) If P₀₁(L)=90 and P₀₁(P)=40 , then P₀₁(D-B) is _____. A. 65 B. 50 C. 25 D. 130

If \(P_{01}(L)=90\) and \(P_{01}(P)=40\), then \(P_{01}(D-B)\) is _____.

Q.4 (A) (iv) If \(P_{01}(L)=90\) and \(P_{01}(P)=40\), then \(P_{01}(D-B)\) is _____.

A. 65

B. 50

C. 25

D. 130

Doubtly Asked 28 Oct 2026 Board exam · March 2025 hsc 12th Save WhatsApp Report

Best answer

Answer: A. 65

Answer: (a) 65

Dorbish–Bowley's index is the arithmetic mean of Laspeyre's and Paasche's indices: \(P_{01}(D-B)=\frac{P_{01}(L)+P_{01}(P)}{2}=\frac{90+40}{2}=65\).

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

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