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Answer: 1.5

Let X = number of heads in three tosses; X takes values 0, 1, 2, 3. Out of 8 equally likely outcomes, the counts are 1, 3, 3, 1.

x0123
P(x)\(\frac{1}{8}\)\(\frac{3}{8}\)\(\frac{3}{8}\)\(\frac{1}{8}\)
\(x\,P(x)\)0\(\frac{3}{8}\)\(\frac{6}{8}\)\(\frac{3}{8}\)

\(E(X)=\Sigma x\,P(x)=\frac{0+3+6+3}{8}=\frac{12}{8}=1.5\)

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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