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Chapter: Magnetic Fields due to Electric Current· Physics

A circular coil of wire is made up of 200 turns, each of radius 10 cm. If a current of 0.5A passes through it, what will be the magnetic field at the centre of the coil?

Q.15 A circular coil of wire is made up of 200 turns, each of radius 10 cm. If a current of 0.5A passes through it, what will be the magnetic field at the centre of the coil?

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Answer: \(B = 2\pi\times10^{-4}\) T \(\approx 6.284\times10^{-4}\) T

Given: \(N = 200\), \(R = 10\) cm \(= 0.1\) m, \(I = 0.5\) A, \(\mu_0 = 4\pi\times10^{-7}\) Wb/A m.

Magnetic field at the centre of a circular coil: \(B = \dfrac{\mu_0 N I}{2R}\)

\(B = \dfrac{4\pi\times10^{-7}\times200\times0.5}{2\times0.1} = \dfrac{4\pi\times10^{-5}}{0.2} = 2\pi\times10^{-4}\) T

\(= 2\times3.142\times10^{-4} = 6.284\times10^{-4}\) T, directed along the axis of the coil.

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report
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