Q.1 (A) (iii) ∫(1-x)⁻³ dx= _____. A. 1/2(1-x)⁻²+c B. 1/2(1+x)⁻²+c C. 1/2(1-x)⁻²+x/2+c D. 1/2(1-x)⁻²-x/2+c

Answer: (a) 1/2(1-x)⁻²+c ∫(1-x)⁻³dx=frac(1-x)⁻²(-2)(-1)+c=1/2(1-x)⁻²+c.

\(\int(1-x)^{-3}\,dx=\) _____.

Q.1 (A) (iii) \(\int(1-x)^{-3}\,dx=\) _____.

A. \(\frac{1}{2}(1-x)^{-2}+c\)

B. \(\frac{1}{2}(1+x)^{-2}+c\)

C. \(\frac{1}{2}(1-x)^{-2}+\frac{x}{2}+c\)

D. \(\frac{1}{2}(1-x)^{-2}-\frac{x}{2}+c\)

Doubtly Asked 29 Oct 2026 Board exam · July 2025 hsc 12th Save WhatsApp Report

Best answer

Answer: (a) \(\frac{1}{2}(1-x)^{-2}+c\)

\(\int(1-x)^{-3}dx=\frac{(1-x)^{-2}}{(-2)(-1)}+c=\frac{1}{2}(1-x)^{-2}+c\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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