Q.4 (A) (iv) If P₀₁(L)=120.4 and P₀₁(P)=130.6 then P₀₁(D-B) is ____ A. 25.1 B. 60.2 C. 125.5 D. 65.3

If \(P_{01}(L)=120.4\) and \(P_{01}(P)=130.6\) then \(P_{01}(D\text{-}B)\) is ____

Q.4 (A) (iv) If \(P_{01}(L)=120.4\) and \(P_{01}(P)=130.6\) then \(P_{01}(D\text{-}B)\) is ____

A. 25.1

B. 60.2

C. 125.5

D. 65.3

Doubtly Asked 29 Oct 2026 Board exam · July 2025 hsc 12th Save WhatsApp Report

Best answer

Answer: (c) 125.5

Dorbish-Bowley's index is the A.M. of Laspeyre's and Paasche's indices: \(P_{01}(D\text{-}B)=\frac{120.4+130.6}{2}=\frac{251}{2}=125.5\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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