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Chapter: Time Series· Mathematics & Statistics (Commerce) Part 2

Following table shows the all India Infant Mortality Rates (per '000) for years 1980 to 1986:Years1980198119821983198419851986IMR10653310Fit a trend line to the above data by the method of least squares.

Q.5 (B) (ii) Following table shows the all India Infant Mortality Rates (per '000) for years 1980 to 1986:

Years1980198119821983198419851986
IMR10653310

Fit a trend line to the above data by the method of least squares.

1 answer

Best answer

Answer: Trend line \(y=4-1.5u\), where \(u=t-1983\)

Here \(n=7\) (odd), so take \(u=t-1983\) (the middle year).

Year \(t\)IMR \(y\)\(u=t-1983\)\(u^2\)\(uy\)Trend value \(4-1.5u\)
198010\(-3\)9\(-30\)8.5
19816\(-2\)4\(-12\)7
19825\(-1\)1\(-5\)5.5
198330004
198431132.5
198512421
19860390\(-0.5\)
Total28028\(-42\)

Normal equations: \(\sum y=na+b\sum u\) and \(\sum uy=a\sum u+b\sum u^2\).
Since \(\sum u=0\): \(a=\frac{\sum y}{n}=\frac{28}{7}=4\), \(b=\frac{\sum uy}{\sum u^2}=\frac{-42}{28}=-1.5\).

The equation of the trend line is \(y=4-1.5u\), where \(u=t-1983\). The trend values are shown in the last column; the IMR shows a falling trend.

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