Chapter: Electrostatics· Physics

When 2 × 1010 electrons are transferred from one conductor to another, a potential difference of 20V appears between the conductors. Find the capacitance of the two conductors.

Q.25 When 2 × 10¹⁰ electrons are transferred from one conductor to another, a potential difference of 20V appears between the conductors. Find the capacitance of the two conductors.

Doubtly Asked 29 Oct 2026 Board exam · July 2024 hsc 12th Save WhatsApp Report

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Answer: \(C = 1.6\times10^{-10}\) F \(= 160\) pF

Charge transferred:

\[q = ne = 2\times10^{10}\times1.6\times10^{-19} = 3.2\times10^{-9}\ \mathrm{C}\]

Capacitance:

\[C = \frac{q}{V} = \frac{3.2\times10^{-9}}{20} = 1.6\times10^{-10}\ \mathrm{F} = 160\ \mathrm{pF}\]

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report

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When 2 × 1010 electrons are transferred from one conductor to another, a potential difference of 20V appears between the conductors. Find the capacitance of the two conductors.

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