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Chapter: Electrochemistry· Chemistry

What is the mass of Cu metal produced at the cathode during the passage of 5 ampere of current through CuSO4 solution for 100 minutes? [ Molar mass of Cu = 63.5 g mol–1 ]

Q.7 What is the mass of Cu metal produced at the cathode during the passage of 5 ampere of current through CuSO4 solution for 100 minutes? [ Molar mass of Cu = 63.5 g mol–1 ]

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Answer: Mass of Cu deposited ≈ 9.87 g

Quantity of electricity: \(Q = It = 5 \times 100 \times 60 = 30000\) C

Moles of electrons \(= \dfrac{Q}{F} = \dfrac{30000}{96500} = 0.3109\) mol

Cathode reaction: Cu2+ + 2e− → Cu, so moles of Cu \(= \dfrac{0.3109}{2} = 0.1554\) mol

Mass of Cu \(= 0.1554 \times 63.5 = 9.87\) g

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report
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