Chapter: Matrices· Mathematics & Statistics (Commerce) Part 1

If \(x + y + z = 3,\ x + 2y + 3z = 4,\ x + 4y + 9z = 6\) then \((y, z) =\) _____.

Q.1 (A)(ii) If \(x + y + z = 3,\ x + 2y + 3z = 4,\ x + 4y + 9z = 6\) then \((y, z) =\) _____.

A. \((-1, 0)\)

B. \((1, 0)\)

C. \((1, -1)\)

D. \((-1, 1)\)

Doubtly Asked 29 Oct 2026 Board exam · March 2024 hsc 12th Save WhatsApp Report

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Answer: (b) \((1, 0)\)

Subtracting the first equation from the second: \(y + 2z = 1\). Subtracting the second from the third: \(2y + 6z = 2\), i.e. \(y + 3z = 1\). Subtracting these two results gives \(z = 0\), so \(y = 1\) (and then \(x = 2\)). Hence \((y, z) = (1, 0)\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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If \(x + y + z = 3,\ x + 2y + 3z = 4,\ x + 4y + 9z = 6\) then \((y, z) =\) _____.

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