Q.1 (A)(iv) The equation of tangent to the curve y = x² + 4x + 1 at P(-1, -2) is ____. A. 2x - y = 0 B. x + 2y + 5 = 0 C. 2x + 4 = 3y D. 5x + y = 1

Answer: (a) 2x - y = 0 dy/dx = 2x + 4. At x = -1, slope m = 2(-1) + 4 = 2. Tangent at (-1, -2): y + 2 = 2(x + 1), i.e. y = 2x, i.e. 2x - y = 0.

The equation of tangent to the curve \(y = x^2 + 4x + 1\) at \(P(-1, -2)\) is ____.

Q.1 (A)(iv) The equation of tangent to the curve \(y = x^2 + 4x + 1\) at \(P(-1, -2)\) is ____.

A. \(2x - y = 0\)

B. \(x + 2y + 5 = 0\)

C. \(2x + 4 = 3y\)

D. \(5x + y = 1\)

Doubtly Asked 29 Oct 2026 Board exam · July 2024 hsc 12th Save WhatsApp Report

Best answer

Answer: (a) \(2x - y = 0\)

\(\dfrac{dy}{dx} = 2x + 4\). At \(x = -1\), slope \(m = 2(-1) + 4 = 2\).

Tangent at \((-1, -2)\): \(y + 2 = 2(x + 1)\), i.e. \(y = 2x\), i.e. \(2x - y = 0\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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