Chapter: Trigonometry· Mathematics Part 2 (Geometry)
Answer: \(30\sqrt3 = 51.9\) m
[Figure: String AC = 60 m from the point C on the ground to the kite A; AB is perpendicular to the ground; \(\angle ACB = 60^\circ\).]
In right-angled ΔABC: \(\sin 60^\circ = \dfrac{AB}{AC}\) \(\therefore \dfrac{\sqrt3}{2} = \dfrac{AB}{60}\)
\(\therefore AB = 30\sqrt3 = 30 \times 1.73 = 51.9\) m. The kite is 51.9 m above the ground.