Chapter: Mensuration· Mathematics Part 2 (Geometry)

A tent is in the shape of a cylinder of diameter 14 m and height 3 m, surmounted by a cone of the same base whose slant height is 10 m. Find the area of canvas needed for the tent (floor not covered) and its cost at ₹ 50 per m\(^2\). \(\left(\pi = \d…

A tent is in the shape of a cylinder of diameter 14 m and height 3 m, surmounted by a cone of the same base whose slant height is 10 m. Find the area of canvas needed for the tent (floor not covered) and its cost at ₹ 50 per m\(^2\). \(\left(\pi = \dfrac{22}{7}\right)\)

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

1 answer

Best answer

Answer: Canvas = 352 m\(^2\); cost = ₹ 17,600

[Figure: Cylindrical lower part (r = 7 m, h = 3 m) with a conical top (r = 7 m, l = 10 m).]

Canvas = CSA of cylinder + CSA of cone \(= 2\pi r h + \pi r l = \pi r (2h + l)\)

\(= \dfrac{22}{7} \times 7 \times (6 + 10) = 22 \times 16 = 352\) m\(^2\).

Cost = 352 × 50 = ₹ 17,600.

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

Was this answer helpful?

A tent is in the shape of a cylinder of diameter 14 m and height 3 m, surmounted by a cone of the same base whose slant height is 10 m. Find the area of canvas needed for the tent (floor not covered) and its cost at ₹ 50 per m\(^2\). \(\left(\pi = \d…

1 answer

Your answer