Asked in: March 2024 board paper; a 3-mark formula-method sum came in July 2024 ( y² + 1/3y = 2 ), March 2025 ( x² - 2x - 3 = 0) and June 2026 ( x² - 3x - 2 = 0) too Solve the following quadratic equation by formula method: 3m² - m - 10 = 0

Answer: m = 2 or m = -5/3 a = 3, b = -1, c = -10 b² - 4ac = (-1)² - 4(3)(-10) = 1 + 120 = 121 m = (-b ± √(b² - 4ac))/2a = (1 ± √(121))/6 = (1 ± 11)/6 m = 12/6 = 2 or m = (-10)/6 = -5/3

Chapter: Quadratic Equations· Mathematics Part 1 (Algebra)

Asked in: March 2024 board paper; a 3-mark formula-method sum came in July 2024 (\(y^2 + \dfrac{1}{3}y = 2\)), March 2025 (\(x^2 - 2x - 3 = 0\)) and June 2026 (\(x^2 - 3x - 2 = 0\)) tooSolve the following quadratic equation by formula method : \(3m^2…

Asked in: March 2024 board paper; a 3-mark formula-method sum came in July 2024 (\(y^2 + \dfrac{1}{3}y = 2\)), March 2025 (\(x^2 - 2x - 3 = 0\)) and June 2026 (\(x^2 - 3x - 2 = 0\)) too

Solve the following quadratic equation by formula method : \(3m^2 - m - 10 = 0\)

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: \(m = 2\) or \(m = -\dfrac{5}{3}\)

\(a = 3\), \(b = -1\), \(c = -10\)

\(b^2 - 4ac = (-1)^2 - 4(3)(-10) = 1 + 120 = 121\)

\(m = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \dfrac{1 \pm \sqrt{121}}{6} = \dfrac{1 \pm 11}{6}\)

\(m = \dfrac{12}{6} = 2\) or \(m = \dfrac{-10}{6} = -\dfrac{5}{3}\)

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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Asked in: March 2024 board paper; a 3-mark formula-method sum came in July 2024 (\(y^2 + \dfrac{1}{3}y = 2\)), March 2025 (\(x^2 - 2x - 3 = 0\)) and June 2026 (\(x^2 - 3x - 2 = 0\)) tooSolve the following quadratic equation by formula method : \(3m^2…

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