Chapter: Quadratic Equations· Mathematics Part 1 (Algebra)
Answer: \(x = \dfrac{2}{3}\) or \(x = -\dfrac{1}{2}\)
\(ac = 6 \times (-2) = -12\); we need two numbers with product −12 and sum −1: \(-4\) and \(3\).
\(6x^2 - 4x + 3x - 2 = 0\)
\(2x(3x - 2) + 1(3x - 2) = 0\)
\((3x - 2)(2x + 1) = 0\)
\(x = \dfrac{2}{3}\) or \(x = -\dfrac{1}{2}\)