Chapter: Quadratic Equations· Mathematics Part 1 (Algebra)
Answer: \(x = -1\) or \(x = -\dfrac{8}{5}\)
\(a = 5\), \(b = 13\), \(c = 8\)
\(b^2 - 4ac = 169 - 160 = 9\)
\(x = \dfrac{-13 \pm \sqrt{9}}{2 \times 5} = \dfrac{-13 \pm 3}{10}\)
\(x = \dfrac{-10}{10} = -1\) or \(x = \dfrac{-16}{10} = -\dfrac{8}{5}\)