Chapter: Arithmetic Progression· Mathematics Part 1 (Algebra)
Answer: \(t_{19} = 115\)
\(a = 7\), \(d = 13 - 7 = 6\), \(n = 19\)
\(t_n = a + (n - 1)d\)
\(t_{19} = 7 + (19 - 1) \times 6 = 7 + 108 = 115\)
(March 2026: \(t_{24} = 12 + 23 \times 4 = 104\).)