Chapter: Arithmetic Progression· Mathematics Part 1 (Algebra)
Answer: 560 is the 63rd term
\(a = 2\), \(d = 9\), \(t_n = 560\)
\(t_n = a + (n - 1)d \Rightarrow 560 = 2 + (n - 1) \times 9\)
\(558 = (n - 1) \times 9 \Rightarrow n - 1 = 62 \Rightarrow n = 63\)