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Chapter: Arithmetic Progression· Mathematics Part 1 (Algebra)

Asked in: July 2025 board paperIn an A.P. sum of three consecutive terms is 27 and their product is 504. Complete the following activity to find the terms.Activity :Let three consecutive terms be \(a - d\), \(a\), \(a + d\).\(\therefore a - d + a + a…

Asked in: July 2025 board paper

In an A.P. sum of three consecutive terms is 27 and their product is 504. Complete the following activity to find the terms.

Activity :
Let three consecutive terms be \(a - d\), \(a\), \(a + d\).
\(\therefore a - d + a + a + d = \) ____
\(\therefore a = \) ____
Similarly : \((a - d) \times a \times (a + d) = \) ____
\(\therefore [(9)^2 - d^2] \times 9 = 504\)
\(\therefore (81 - d^2) \times 9 = 504\)
\(\therefore d^2 = 81 - \) ____
\(\therefore d = \pm 5\)
Thus by putting \(a = 9\) and \(d = 5\) we get three consecutive terms = ____
Or by putting \(a = 9\) and \(d = -5\) we get three consecutive terms = ____

1 answer

Best answer

Answer: 27; \(a = 9\); 504; \(81 - 56\); terms 4, 9, 14 or 14, 9, 4

\(3a = 27 \Rightarrow a = 9\)

\((a - d) \times a \times (a + d) = 504\)

\((81 - d^2) \times 9 = 504 \Rightarrow 81 - d^2 = 56 \Rightarrow d^2 = 81 - 56 = 25 \Rightarrow d = \pm 5\)

\(d = 5\): terms \(9 - 5, 9, 9 + 5\) = 4, 9, 14

\(d = -5\): terms 14, 9, 4

Check: \(4 + 9 + 14 = 27\), \(4 \times 9 \times 14 = 504\) ✓.

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