Chapter: Arithmetic Progression· Mathematics Part 1 (Algebra)
Answer: Yes, the interest amounts form an A.P.; interest after 10 years = ₹ 2,000
Simple interest for 1 year \(= \dfrac{P \times R \times N}{100} = \dfrac{2000 \times 10 \times 1}{100} = ₹\ 200\).
Interest after 2 years \(= ₹\ 400\); after 3 years \(= ₹\ 600\); and so on.
Sequence: 200, 400, 600, …; \(t_2 - t_1 = 200\), \(t_3 - t_2 = 200\). The difference is constant, so it is an A.P. with \(a = 200\), \(d = 200\).
\(t_{10} = a + 9d = 200 + 9 \times 200 = 2000\)
Interest after 10 years = ₹ 2,000.