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Answer: 20 months

Payments form an A.P.: \(a = 30500\), \(d = -1500\), \(S_n = 325000\).

\(325000 = \dfrac{n}{2}[2 \times 30500 + (n - 1)(-1500)]\)

\(650000 = n[61000 - 1500n + 1500] = n(62500 - 1500n)\)

Divide by 500: \(1300 = n(125 - 3n)\)

\(3n^2 - 125n + 1300 = 0\)

\(n = \dfrac{125 \pm \sqrt{15625 - 15600}}{6} = \dfrac{125 \pm 5}{6}\)

\(n = 20\) or \(n = \dfrac{130}{6}\) (not a whole number, rejected).

He will clear the amount in 20 months. Check: \(t_{20} = 30500 - 19 \times 1500 = 2000\); \(S_{20} = 10(30500 + 2000) = 325000\) ✓.

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report
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