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Chapter: Probability· Mathematics Part 1 (Algebra)

Asked in: July 2025 board paper; March 2024 board paper (2 marks: probability of a face card)Q.7 A card is drawn from a well shuffled pack of 52 playing cards. Complete the following activity to find the probability of the following events:(a) A red…

Asked in: July 2025 board paper; March 2024 board paper (2 marks: probability of a face card)

Q.7 A card is drawn from a well shuffled pack of 52 playing cards. Complete the following activity to find the probability of the following events:
(a) A red card (b) A face card.

Activity:
Let ‘S’ is the sample space \(\therefore\) n(S) = ____
Event A: Card drawn is a red card. Total red cards = ____ \(\therefore\) n(A) = ____
\(\therefore P(A) = \dfrac{n(A)}{n(S)}\) ...... Formula
\(\therefore P(A) = \dfrac{26}{52}\) \(\therefore\) P(A) = ____
Event B: Card drawn is a face card. Total face cards = 12 \(\therefore\) n(B) = ____
\(\therefore P(B) = \dfrac{n(B)}{n(S)}\) ...... Formula
\(\therefore P(B) = \dfrac{12}{52}\) \(\therefore\) P(B) = ____

1 answer

Best answer

Answer: (a) \(P(A) = \dfrac{1}{2}\) (b) \(P(B) = \dfrac{3}{13}\)

n(S) = 52

Red cards are hearts and diamonds: 13 + 13 = 26, so n(A) = 26 and \(P(A) = \dfrac{26}{52} = \dfrac{1}{2}\).

Face cards are King, Queen and Jack of each of the 4 suits: 3 × 4 = 12, so n(B) = 12 and \(P(B) = \dfrac{12}{52} = \dfrac{3}{13}\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report
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