Chapter: Probability· Mathematics Part 1 (Algebra)
Answer: \(P(A) = \dfrac{1}{4}\), \(P(B) = \dfrac{1}{4}\)
S = {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}, n(S) = 12
Event A: head and a prime number (2, 3, 5). A = {H2, H3, H5}, n(A) = 3
\(P(A) = \dfrac{3}{12} = \dfrac{1}{4}\)
Event B: tail and an odd number (1, 3, 5). B = {T1, T3, T5}, n(B) = 3
\(P(B) = \dfrac{3}{12} = \dfrac{1}{4}\)