Chapter: Statistics· Mathematics Part 1 (Algebra)

Asked in: March 2025 board paperQ.8 In a general store the prices of different articles and its demand is shown in the following frequency distribution table. Find the median of the prices.Price in rupeesNo. of articlesLess than 2014020–4010040–60806…

Asked in: March 2025 board paper

Q.8 In a general store the prices of different articles and its demand is shown in the following frequency distribution table. Find the median of the prices.

Price in rupees	No. of articles
Less than 20	140
20–40	100
40–60	80
60–80	60
80–100	20

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Answer: Median price = ₹ 32

“Less than 20” is the class 0–20.

Class	Frequency	Cumulative frequency (less than)
0–20	140	140
20–40	100	240
40–60	80	320
60–80	60	380
80–100	20	400

N = 400, \(\dfrac{N}{2} = 200\). The first cumulative frequency greater than 200 is 240, so median class = 20–40.

L = 20, cf = 140, f = 100, h = 20

\(\text{Median} = L + \left[ \dfrac{\frac{N}{2} - cf}{f} \right] \times h\)

\(= 20 + \left[ \dfrac{200 - 140}{100} \right] \times 20 = 20 + 12 = 32\)

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Asked in: March 2025 board paperQ.8 In a general store the prices of different articles and its demand is shown in the following frequency distribution table. Find the median of the prices.Price in rupeesNo. of articlesLess than 2014020–4010040–60806…

1 answer

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