Chapter: Statistics· Mathematics Part 1 (Algebra)

Asked in: July 2025 board paper; a 4-mark median of grouped data also came in March 2026Q.9 In the following frequency distribution table ages of 300 patients and number of patients in a hospital is given. Find the median age of the patients.Age (in…

Asked in: July 2025 board paper; a 4-mark median of grouped data also came in March 2026

Q.9 In the following frequency distribution table ages of 300 patients and number of patients in a hospital is given. Find the median age of the patients.

Age (in years)	10–20	20–30	30–40	40–50	50–60	60–70
Number of patients	60	42	55	70	53	20

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: Median age = 38.73 years (approx.)

Class	Frequency	Cumulative frequency
10–20	60	60
20–30	42	102
30–40	55	157
40–50	70	227
50–60	53	280
60–70	20	300

N = 300, \(\dfrac{N}{2} = 150\). The first cumulative frequency greater than 150 is 157, so median class = 30–40.

L = 30, cf = 102, f = 55, h = 10

\(\text{Median} = L + \left[ \dfrac{\frac{N}{2} - cf}{f} \right] \times h\)

\(= 30 + \left[ \dfrac{150 - 102}{55} \right] \times 10 = 30 + \dfrac{480}{55} = 30 + 8.73 = 38.73\)

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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Asked in: July 2025 board paper; a 4-mark median of grouped data also came in March 2026Q.9 In the following frequency distribution table ages of 300 patients and number of patients in a hospital is given. Find the median age of the patients.Age (in…

1 answer

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