Q.19 For a grouped frequency distribution the modal class is 40–50 with f₁ = 24, f₀ = 18 and f₂ = 12. Find the mode.

Answer: Mode = 43.33 (approx.) L = 40, h = 10 Mode = L + [ (f₁ - f₀)/(2f₁ - f₀ - f₂) ] × h = 40 + [ (24 - 18)/(48 - 18 - 12) ] × 10 = 40 + 6/18 × 10 = 40 + 3.33 = 43.33

Chapter: Statistics· Mathematics Part 1 (Algebra)

For a grouped frequency distribution the modal class is 40–50 with \(f_1 = 24\), \(f_0 = 18\) and \(f_2 = 12\). Find the mode.

Q.19 For a grouped frequency distribution the modal class is 40–50 with \(f_1 = 24\), \(f_0 = 18\) and \(f_2 = 12\). Find the mode.

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: Mode = 43.33 (approx.)

L = 40, h = 10

\(\text{Mode} = L + \left[ \dfrac{f_1 - f_0}{2f_1 - f_0 - f_2} \right] \times h\)

\(= 40 + \left[ \dfrac{24 - 18}{48 - 18 - 12} \right] \times 10 = 40 + \dfrac{6}{18} \times 10 = 40 + 3.33 = 43.33\)

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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For a grouped frequency distribution the modal class is 40–50 with \(f_1 = 24\), \(f_0 = 18\) and \(f_2 = 12\). Find the mode.

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