In \(\Delta PQR\), seg ST || side QR, P – S – Q and P – T – R. If PS = 3, SQ = 6 and PT = 4, find TR.

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: TR = 8

By the basic proportionality theorem, \(\dfrac{PS}{SQ} = \dfrac{PT}{TR}\) \(\therefore \dfrac{3}{6} = \dfrac{4}{TR}\) \(\therefore TR = 8\).

Doubtly AI · 29 Oct 2026 AI-verified · Nov 2026 Report

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