Asked in: March 2026 board paper (a 45°–45°–90° activity was also asked in March 2026)In \(\Delta RST\), \(\angle S = 90^\circ\), \(\angle T = 30^\circ\), RT = 12 cm, then find RS and ST.

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: RS = 6 cm, ST = \(6\sqrt{3}\) cm

\(\angle S = 90^\circ\), \(\angle T = 30^\circ\), so \(\angle R = 60^\circ\). \(\Delta RST\) is a 30°–60°–90° triangle with hypotenuse RT.

Side opposite 30°: \(RS = \dfrac{1}{2} \times RT = \dfrac{1}{2} \times 12 = 6\) cm (30°–60°–90° theorem).

Side opposite 60°: \(ST = \dfrac{\sqrt{3}}{2} \times RT = \dfrac{\sqrt{3}}{2} \times 12 = 6\sqrt{3}\) cm.

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report

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