Answer: A. 3 Answer: (A) 3 By Apollonius theorem, AB² + AC² = 2AD² + 2BD² . BD = 4, so 50 = 2AD² + 32 therefore AD² = 9 therefore AD = 3 .

In \(\Delta ABC\), D is the midpoint of BC. If \(AB^2 + AC^2 = 50\) and BC = 8, then AD = ?

A. 3

B. 4

C. 5

D. 9

Doubtly Asked 29 Oct 2026 Practice test ssc 10th Save WhatsApp Report

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Answer: A. 3

Answer: (A) 3

By Apollonius theorem, \(AB^2 + AC^2 = 2AD^2 + 2BD^2\). BD = 4, so \(50 = 2AD^2 + 32\) \(\therefore AD^2 = 9\) \(\therefore AD = 3\).

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report

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